Sunday, September 11, 2022

Problem

If

$$ x+\frac{1}{x}=2, $$

find the value of

$$ x^5+\frac{1}{x^5}. $$

 If \x+1/x=2\ Find the value of \x^5+1/x^5\

As we had: `x+1/x=2` `rightarrow(x+1/x)^2=4` `leftrightarrowx^2+1/x^2=2`

We continue with `(x^2+1/x^2)(x+1/x)=4` `leftrightarrowx^3+x+1/x+1/x^3=4`

                                `leftrightarrowx^3+1/x^3=2`

Friday, September 9, 2022

Vietnamese Mathematical Olympiad 2022

Let \(a\), \(b\), and \(c\) be the roots of the equation

$$ x^3-x^2-1=0. $$

Find the value of

$$ \frac{1}{a^{2023}}+\frac{1}{b^{2023}}+\frac{1}{c^{2023}}. $$

Let \(a\), \(b\), and \(c\) be nonzero real numbers satisfying

$$ a+b+c=2022, $$ and $$ \frac{1}{a}+\frac{1}{b}+\frac{1}{c}=\frac{1}{2022}. $$

Find the value of

$$ \frac{1}{a^{2023}}+\frac{1}{b^{2023}}+\frac{1}{c^{2023}}. $$


Solution